Garrett Temple has signed a deal with the Brooklyn Nets for the next two years of his career. According to Marc Spears from ESPN, the contract is worth $10 Million and it includes a team option in the second year of the deal.
Free agent guard Garrett Temple is expected to sign a two-year, $10 million deal with the Brooklyn Nets, a source told ESPN's The Undefeated. Team option second year.
— Marc J. Spears (@MarcJSpearsESPN) June 30, 2019
The Nets made official the signing on Monday and released a statement welcoming Temple to the team. In the statement, the Nets General Manager Sean Marks talked about the fit of Temple for the team.
“Garrett is an excellent culture fit who can guard multiple positions and provide a stabilizing presence on both ends of the court,” said Nets General Manager Sean Marks. “His high IQ and strong leadership qualities will be welcome additions to our team. We look forward to welcoming Garrett and his family to Brooklyn.”
Temple played for several teams in his first seasons in the NBA including the Houston Rockets, Sacramento Kings, San Antonio Spurs, Milwaukee Bucks, and the Charlotte Hornets. In 2012, Temple found some stability when he signed a deal with the Washington Wizards and remained there for four seasons.
After, he would sign with the Sacramento Kings and stay there for two seasons until they traded him to the Memphis Grizzlies in this past season. Then, the Grizzlies traded him to the Los Angeles Clippers and he would end the season with the Clippers.
In his career, Temple has played nine seasons and a total of 514 games. Temple has averages of 5.9 points, 2.1 rebounds and 1.6 assists in 20.3 minutes per game while shooting 35.3 percent from the three-point line.
